CBSE 10th Class past year question paper
Year 2019
SET 1, Code Number- 30/2/1
Question number – 16
Deepak BoraNewbie
Find the ratio in which the line x – 3y = 0 divides the line segment joining the points (– 2, – 5) and (6, 3). Find the coordinates of the point of intersection.
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Let the line x – 3y = 0 intersect the segment
joining A(–2, –5) and B(6, 3) in the ratio k : 1
∴ Coordinates of P are [ {(6k – 2) / ( k + 1)}, { ( 3 k – 5 ) / ( k + 1)} ]
P lies on x – 3y = 0
{(6k – 2) / ( k + 1)} = 3 { ( 3 k – 5 ) / ( k + 1)}
k = 13/3
∴ Ratio is 13 : 3
Coordinates of P are [ ( 9/2), (3/2) ]