This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.
Here x-intercept and y-intercept is given.
So, you have to find the equation of the line
This is the Question Number 25, Exercise 12.1 of M.L Aggarwal.
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Find the equation of the line whose x-intercept is 6 and y-intercept is – 4.
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Given, x-intercept of a line is 6
So,
The line will pass through the point (6, 0)
Also given, the y -intercept of the line is -4 ⇒ c = -4
So, the line will pass through the point (0, -4)
Now,
Slope, m = m = y2 – y1/ x2 – x1
m = (-4 – 0)/(0 – 6) = -4/-6 = 2/3
Thus, the equation of the line is given by
y = mx + c
y = (2/3)x + (-4)
3y = 2x – 12
⇒ 2x – 3y – 12 = 0