This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.

Here x-intercept and y-intercept is given.

So, you have to find the equation of the line

This is the Question Number 25, Exercise 12.1 of M.L Aggarwal.

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# Find the equation of the line whose x-intercept is 6 and y-intercept is – 4.

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Given, x-intercept of a line is 6

So,

The line will pass through the point (6, 0)

Also given, the y -intercept of the line is -4 ⇒ c = -4

So, the line will pass through the point (0, -4)

Now,

Slope, m = m = y

_{2}– y_{1}/ x_{2}– x_{1}m = (-4 – 0)/(0 – 6) = -4/-6 = 2/3

Thus, the equation of the line is given by

y = mx + c

y = (2/3)x + (-4)

3y = 2x – 12

⇒ 2x – 3y – 12 = 0