ICSE Board Question Based on Equation of a Straight Line Chapter of M.L Aggarwal for class10
In this question a line given that is parallel and passes through the mid-point of the line segment joining the points given as per the question.
This is the Question Number 19, Exercise 12.2 of M.L Aggarwal.
Deepak BoraNewbie
Find the equation of the line that is parallel to 2x + 5y – 7 = 0 and passes through the mid-point of the line segment joining the points (2, 7) and (– 4, 1).
Share
Given line: 2x + 5y – 7 = 0
5y = -2x + 7
y = (-2/5) x + 7/5
So, the slope is -2/5
Hence, the slope of the line that is parallel to the given line will be the same, m = -2/5
Now, the mid-point of the line segment joining points (2, 7) and (– 4, 1) is
((2 – 4)/2, (7 + 1)/2) = (-1, 4)
Thus, the equation of the line will be
y – y1 = m (x – x1)
y – 4 = (-2/5) (x + 1)
5y – 20 = -2x -2
2x + 5y = 18