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Deepak Bora
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Find the equation of the line that is parallel to 2x + 5y – 7 = 0 and passes through the mid-point of the line segment joining the points (2, 7) and (– 4, 1).

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ICSE Board Question Based on Equation of a Straight Line Chapter of M.L Aggarwal for class10
In this question a line given that is parallel and passes through the mid-point of the line segment joining the points given as per the question.
This is the Question Number 19, Exercise 12.2 of M.L Aggarwal.

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1 Answer

  1. Given line: 2x + 5y – 7 = 0

    5y = -2x + 7

    y = (-2/5) x + 7/5

    So, the slope is -2/5

    Hence, the slope of the line that is parallel to the given line will be the same, m = -2/5

    Now, the mid-point of the line segment joining points (2, 7) and (– 4, 1) is

    ((2 – 4)/2, (7 + 1)/2) = (-1, 4)

    Thus, the equation of the line will be

    y – y1 = m (x – x1)

    y – 4 = (-2/5) (x + 1)

    5y – 20 = -2x -2

    2x + 5y = 18

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