This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.

Here you have to find the equation of line passing through the point (2, – 5) and making an intercept of – 3 on the y-axis.

I have confusion in this question so please solve it.

This is the Question Number 13 , Exercise 12.1 of M.L Aggarwal.

Deepak BoraNewbie

# Find the equation of the line passing through the point (2, – 5) and making an intercept of – 3 on the y-axis.

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Given, a line equation passes through point (2, -5) and makes a y-intercept of -3

We know that,

The equation of line is y = mx + c, where m is the slope and c is the y-intercept

So, we have

y = mx – 3

Now, this line equation will satisfy the point (2, -5)

-5 = m (2) – 3

-5 = 2m – 3

2m = 3 – 5 = -2

⇒ m = -1

Hence, the equation of the line is y = -x + (-3) ⇒ x + y + 3 = 0