This is the Important question of class 10 Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD.
Here you have to find the equation of line passing through the point (2, – 5) and making an intercept of – 3 on the y-axis.
I have confusion in this question so please solve it.
This is the Question Number 13 , Exercise 12.1 of M.L Aggarwal.
Deepak BoraNewbie
Find the equation of the line passing through the point (2, – 5) and making an intercept of – 3 on the y-axis.
Share
Given, a line equation passes through point (2, -5) and makes a y-intercept of -3
We know that,
The equation of line is y = mx + c, where m is the slope and c is the y-intercept
So, we have
y = mx – 3
Now, this line equation will satisfy the point (2, -5)
-5 = m (2) – 3
-5 = 2m – 3
2m = 3 – 5 = -2
⇒ m = -1
Hence, the equation of the line is y = -x + (-3) ⇒ x + y + 3 = 0