This question is Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD for class 10.
Here you have to the equation of the line passing through a point and parallel to a line.
This is the Question Number 15, Exercise 12.2 of M.L Aggarwal.
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Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.
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Given line: 3x + 5y + 15 = 0
5y = -3x – 15
y = (-3/5) x – 3
So, slope (m) = -3/5
The slope of the line parallel to the given line will the same -3/5
And, the line passes through the point (0, 4)
Hence, equation of the line will be
y – y1 = m (x – x1)
y – 4 = (-3/5) (x – 0)
5y – 20 = -3x
3x + 5y – 20 = 0