Deepak Bora
  • 0

Find the equation of the line passing through (0, 4) and parallel to the line 3x + 5y + 15 = 0.

  • 0

This question is Based on Equation of a Straight Line Chapter of M.L Aggarwal book for ICSE BOARD for class 10.
Here you have to the equation of the line passing through a point and parallel to a line.
This is the Question Number 15, Exercise 12.2 of M.L Aggarwal.

Share

Related Questions

1 Answer

  1. Given line: 3x + 5y + 15 = 0

    5y = -3x – 15

    y = (-3/5) x – 3

    So, slope (m) = -3/5

    The slope of the line parallel to the given line will the same -3/5

    And, the line passes through the point (0, 4)

    Hence, equation of the line will be

    y – y1 = m (x – x1)

    y – 4 = (-3/5) (x – 0)

    5y – 20 = -3x

    3x + 5y – 20 = 0

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.