In coordinate geometry what is the best solution of exercise 7.3 question no. 1 (2) .Give me the easy solution for this question.Find the area of the triangle whose vertices are(ii) (-5, -1), (3, -5), (5, 2).
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Find the area of the triangle whose vertices are(ii) (-5, -1), (3, -5), (5, 2). Q.1(2)
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(ii) Here,
x1 = -5, x2 = 3, x3 = 5, y1 = -1, y2 = -5 and y3 = 2
Area of the triangle = 1/2 [-5 { (-5)- (2)} + 3(2-(-1)) + 5{-1 – (-5)}]
= 1/2{35 + 9 + 20} = 32
Therefore, the area of the triangle is 32 square units.