In areas related to circle of ncert class 10 chapter what is the best solution of the exercise 12.2 of question number 2 . Give me the easiest and simplest solution of this question . Find the area of a quadrant of a circle whose circumference is 22 cm.
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Circumference of the circle, C = 22 cm (given)
It should be noted that a quadrant of a circle is a sector which is making an angle of 90°.
Let the radius of the circle = r
As C = 2πr = 22,
R = 22/2π cm = 7/2 cm
∴ Area of the quadrant = (θ/360°) × πr2
Here, θ = 90°
So, A = (90°/360°) × π r2 cm2
= (49/16) π cm2
= 77/8 cm2 = 9.6 cm2