This is the Important question based on Arithmetic progression Exercise 11 of R S Aggarwal book for ICSE & CBSE Board.
Here the AP is given. you have to find the nth term of given AP.
This is the Question Number 5 Exercise 11 A of RS Aggarwal Solution
Given AP is
6, 7_3 /4 , 9_1 /2 , 11_1 /4 , ………..
Here First Term =a=6
Common Difference :
d= 7_3 /4-6=1_3/4=7/4
Here,First Term=a=6
Common Difference =d = -15-(-40) = -15 + 40 =25
n=37
a_n= a +(n-1)d
a_37= 6 + (37-1)(7/4)
=69
Given AP is
6, 7_3 /4 , 9_1 /2 , 11_1 /4 , ………..
Here First Term
a=6
Common Difference :
d= 7_3 /4-6=1_3/4=7/4
Here,First Term=a=6
Common Difference =d = -15-(-40) = -15 + 40 =25
n=37
a_n= a +(n-1)d
a_37= 6 + (37-1)(7/4)
=69