Adv
AnilSinghBora
  • 0
Guru

Factorize:(ii ) 2×2+y2+8z2–2√2xy+4√2yz–8xz Q.5(2)

  • 0

Hello sir give me the best way for solving the question of Polynomials chapter of exercise 2.5 of question no.5(2) what is the simple way for solving this question give me the best way Factorize:(ii ) 2×2+y2+8z2–2√2xy+4√2yz–8xz

Share

1 Answer

  1. Using identity, (x +y+z)2 = x2+y2+z2+2xy+2yz+2zx

    We can say that, x2+y2+z2+2xy+2yz+2zx = (x+y+z)2

    2x2+y2+8z2–2√2xy+4√2yz–8xz

    = (-√2x)2+(y)2+(2√2z)2+(2×-√2x×y)+(2×y×2√2z)+(2×2√2×−√2x)

    = (−√2x+y+2√2z)2

    = (−√2x+y+2√2z)(−√2x+y+2√2z)

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions