Hello sir give me the best way for solving the question of Polynomials chapter of exercise 2.5 of question no.5(2) what is the simple way for solving this question give me the best way Factorize:(ii ) 2×2+y2+8z2–2√2xy+4√2yz–8xz
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Using identity, (x +y+z)2 = x2+y2+z2+2xy+2yz+2zx
We can say that, x2+y2+z2+2xy+2yz+2zx = (x+y+z)2
2x2+y2+8z2–2√2xy+4√2yz–8xz
= (-√2x)2+(y)2+(2√2z)2+(2×-√2x×y)+(2×y×2√2z)+(2×2√2×−√2x)
= (−√2x+y+2√2z)2
= (−√2x+y+2√2z)(−√2x+y+2√2z)