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Express the trigonometric ratios sin A, sec A and tan A in terms of cot A. Q.1

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How i solve the introduction of trigonometry of class 10 ncert . Find the best way to solve the trigonometry question of exercise 8.4 question number 1  easily, please help me to solve the question in a easiest way.Express the trigonometric ratios sin A, sec A and tan A in terms of cot A

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  1. To convert the given trigonometric ratios in terms of cot functions, use trigonometric formulas

    We know that,

    cosec2A – cot2A = 1

    cosec2A = 1 + cot2A

    Since cosec function is the inverse of sin function, it is written as

    1/sin2A = 1 + cot2A

    Now, rearrange the terms, it becomes

    sin2A = 1/(1+cot2A)

    Now, take square roots on both sides, we get

    sin A = ±1/(√(1+cot2A)

    The above equation defines the sin function in terms of cot function

    Now, to express sec function in terms of cot function, use this formula

    sin2A = 1/ (1+cot2A)

    Now, represent the sin function as cos function

    1 – cos2A = 1/ (1+cot2A)

    Rearrange the terms,

    cos2A = 1 – 1/(1+cot2A)

    ⇒cos2A = (1-1+cot2A)/(1+cot2A)

    Since sec function is the inverse of cos function,

    ⇒ 1/sec2A = cot2A/(1+cot2A)

    Take the reciprocal and square roots on both sides, we get

    ⇒ sec A = ±√ (1+cot2A)/cotA

    Now, to express tan function in terms of cot function

    tan A = sin A/cos A and cot A = cos A/sin A

    Since cot function is the inverse of tan function, it is rewritten as

    tan A = 1/cot A

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