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# Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

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The best method of prime factors of class 10th maths. This is the important question of class 10th. I want to know about factor method of this question. Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

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1. (i) 140

By Taking theÂ LCM of 140, we will get the product of its prime factor.

Therefore, 140 = 2 Ã— 2 Ã— 5 Ã— 7 Ã— 1 = 22Ã—5Ã—7

(ii) 156

By Taking theÂ LCM of 156, we will get the product of its prime factor.

Hence, 156 = 2 Ã— 2 Ã— 13 Ã— 3 Ã— 1 = 22Ã— 13 Ã— 3

(iii) 3825

By Taking theÂ LCM of 3825, we will get the product of its prime factor.

Hence, 3825 = 3 Ã— 3 Ã— 5 Ã— 5 Ã— 17 Ã— 1 = 32Ã—52Ã—17

(iv) 5005

By Taking theÂ LCM of 5005, we will get the product of its prime factor.

Hence, 5005 = 5 Ã— 7 Ã— 11 Ã— 13 Ã— 1 = 5 Ã— 7 Ã— 11 Ã— 13

(v) 7429

By Taking theÂ LCM of 7429, we will get the product of its prime factor.

Hence, 7429 = 17 Ã— 19 Ã— 23 Ã— 1 = 17 Ã— 19 Ã— 23

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