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Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

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The best method of prime factors of class 10th maths. This is the important question of class 10th. I want to know about factor method of this question. Express each number as a product of its prime factors: (i) 140 (ii) 156 (iii) 3825 (iv) 5005 (v) 7429

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  1. (i) 140

    By Taking the LCM of 140, we will get the product of its prime factor.

    Therefore, 140 = 2 × 2 × 5 × 7 × 1 = 22×5×7

    (ii) 156

    By Taking the LCM of 156, we will get the product of its prime factor.

    Hence, 156 = 2 × 2 × 13 × 3 × 1 = 22× 13 × 3

    (iii) 3825

    By Taking the LCM of 3825, we will get the product of its prime factor.

    Hence, 3825 = 3 × 3 × 5 × 5 × 17 × 1 = 32×52×17

    (iv) 5005

    By Taking the LCM of 5005, we will get the product of its prime factor.

    Hence, 5005 = 5 × 7 × 11 × 13 × 1 = 5 × 7 × 11 × 13

    (v) 7429

    By Taking the LCM of 7429, we will get the product of its prime factor.

    Hence, 7429 = 17 × 19 × 23 × 1 = 17 × 19 × 23

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