How can i solve this question of introduction of trigonometry of ncert class 10 , please help me to evaluate the question number 1(1) of exercise 8.3 .Find the best and easiest way to solve this question. Evaluate; sin 18°/cos 72°
Share
Lost your password? Please enter your email address. You will receive a link and will create a new password via email.
sin 18°/cos 72°
To simplify this, convert the sin function into cos function
We know that, 18° is written as 90° – 18°, which is equal to the cos 72°.
= sin (90° – 18°) /cos 72°
Substitute the value, to simplify this equation
= cos 72° /cos 72° = 1