Adv
Sonu
  • 0
Newbie

Evaluate: (ii) sin 25° cos 65° + cos 25° sin 65°. Q.3(2)

  • 0

In ncert class 10 introduction of trigonometry how i solve the exercise 8.4 question number 3(2)  easily . Please help me to find the best way to solve this question in a easiest way . Evaluate: (ii) sin 25° cos 65° + cos 25° sin 65°.

Share

1 Answer

  1. This answer was edited.

    sin 25° cos 65° + cos 25° sin 65°

    To simplify this, convert some of the sin functions into cos functions and cos function into sin function and it becomes,

    = sin(90°-25°) cos 65° + cos (90°-65°) sin 65°

    = cos 65° cos 65° + sin 65° sin 65°

    = cos265° + sin265° = 1 (since sin2A + cos2A = 1)

    Therefore, sin 25° cos 65° + cos 25° sin 65° = 1

    • 0
Leave an answer

Leave an answer

Browse

Choose from here the video type.

Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs".

Captcha Click on image to update the captcha.

Related Questions