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Deepak Bora
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Equation of a straight line

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Find the equation of the line passing through the points A(-1,3) and B(0,2).Hence,show that the points A,B and C(1,1) are collinear.

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  1. The line is passing through the points A(-1,3) and B(0,2)

    m=y2-y1/x2-x1

    = 2-3/0+1

    = -1/1

    = -1

    ∴ equation  (y-y1) = m(x2-x1)

    (y-3) = -1(x+1)

    y-3 = -x-1

    ∴    X+y = 2

    Now if points A,B and C are collinear then  they must lie on the same straight line,which means point C must lie on the line of A and B

    ∴C(1,1)

    Substituting the values in equation

    x+y= 2

    1+1= 2

    2 = 2

    ∴ A,B and C are collinear

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