0 Deepak BoraNewbie Asked: July 3, 20202020-07-03T10:22:55+05:30 2020-07-03T10:22:55+05:30In: CBSE, ICSE The vertices of a triangle ABC are (3,8) , B(-1,2), C(6-6). Find: 1. The slope of BC , 2.Equation of a line perpendicular to BC and passing through A 0 …? equation of a straight linequestionslopestraight linetriangle Share Facebook 1 Answer Voted Oldest Recent Deepak Bora Newbie 2020-07-09T08:32:37+05:30Added an answer on July 9, 2020 at 8:32 am (1) Slope of BC, B(-1,2), C(6,-6) m= y2-y1/x2-x1 m= -6-2/6+1 = -8/7 (2) Let AD⊥ BC (slope of AC)( slope of BC) = -1 (m1)(-8/7) = -1 (m1) = 7/8 And AD is passing through A(3,8) equation of a line (y-y1)= m1(x – x1) y-8= 7/8(x-3) 8y-64= 7x-21 7x-8y+43=0 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment. Related Questions Find the altitude of an equilateral triangle when each of its side is 'a' ? True or false :- Two triangles are similar if their corresponding sides are proportional. What is the length of RT? The points B (1, 3) and D (6, 8) are two opposite vertices of a square ABCD. Find ... Point A (3, – 2) on reflection in the x-axis is mapped as A’ and point B on ...

(1) Slope of BC, B(-1,2), C(6,-6)

m= y2-y1/x2-x1

m= -6-2/6+1

= -8/7

(2)

Let AD⊥ BC

(slope of AC)( slope of BC) = -1

(m1)(-8/7) = -1

(m1) = 7/8

And AD is passing through A(3,8)

equation of a line

(y-y1)= m1(x – x1)

y-8= 7/8(x-3)

8y-64= 7x-21

7x-8y+43=0