What is the easiest way for solving the question of class 9^{th} ncert math of exercise 11.2 of math of Constructions chapter of question no.1 Please help me for the best suggestion of this question Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB+AC = 13 cm.

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# Construct a triangle ABC in which BC = 7cm, ∠B = 75° and AB+AC = 13 cm. Q.1

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Construction Procedure:

The steps to draw the triangle of given measurement is as follows:

1. Draw a line segment of base BC = 7 cm

2. Measure and draw ∠B = 75° and draw the ray BX

3. Take a compass and measure AB+AC = 13 cm.

4. With B as the centre, draw an arc at the point be D

5. Join DC

6. Now draw the perpendicular bisector of the line DC and the intersection point is taken as A.

7. Now join AC

8. Therefore, ABC is the required triangle.