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An oil funnel made of tin sheet consists of a 10 cm long cylindrical portion attached to a frustum of a cone. If the total height is 22 cm, diameter of the cylindrical portion is 8 cm and the diameter of the top of the funnel is 18 cm, find the area of the tin sheet required to make the funnel (see Fig.). Q.5

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Give me the easiest and simple solution of the chapter surface areas and volumes  of ncert class 10th . Find the simple and easiest solution of the exercise 13.5 question number 5 give me the best solution of this question.An oil funnel made of tin sheet consists of a 10 cm long cylindrical portion attached to a frustum of a cone. If the total height is 22 cm, diameter of the cylindrical portion is 8 cm and the diameter of the top of the funnel is 18 cm, find the area of the tin sheet required to make the funnel (see Fig.).

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1 Answer

  1. Given,

    Diameter of upper circular end of frustum part = 18 cm

    So, radius (r1) = 9 cm

    Now, the radius of the lower circular end of frustum (r2) will be equal to the radius of the circular end of the cylinder

    So, r2 = 8/2 = 4 cm

    Now, height (h1) of the frustum section = 22 – 10 = 12 cm

    And,

    Height (h2) of cylindrical section = 10 cm (given)

    Now, the slant height will be-

    Ncert solutions class 10 chapter 13-37

    Or, l = 13 cm

    Area of tin sheet required = CSA of frustum part + CSA of cylindrical part

    = π(r1+r2)l+2πr2h2

    Solving this we get,

    Area of tin sheet required = 782×(4/7) cm2

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