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A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower. Q.15

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I don’t know how to solve the problem of Triangles of exercise 6.3 of class 10th math, please help me to solve the problem of this question A vertical pole of a length 6 m casts a shadow 4m long on the ground and at the same time a tower casts a shadow 28 m long. Find the height of the tower.

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  1. Given, Length of the vertical pole = 6m

    Shadow of the pole = 4 m

    Let Height of tower = h m

    Length of shadow of the tower = 28 m

    Ncert solutions class 10 chapter 6-26

    In ΔABC and ΔDEF,

    ∠C = ∠E (angular elevation of sum)

    ∠B = ∠F = 90°

    ∴ ΔABC ~ ΔDEF (AA similarity criterion)

    ∴ AB/DF = BC/EF (If two triangles are similar corresponding sides are proportional)

    ∴ 6/h = 4/28

    ⇒h = (6×28)/4

    ⇒ h = 6 × 7

    ⇒ = 42 m

    Hence, the height of the tower is 42 m.

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