Today i am solving the ncert class 10 question of chapter surface areas and volume . Find the easiest and simplest way to solve the exercise 13.2 question number 6 . How i solve the question in a simplest and easiest way.A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.

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# A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. Q.6

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Given, the height of the big cylinder (H) = 220 cm

Radius of the base (R) = 24/12 = 12 cm

So, the volume of the big cylinder = πR

^{2}H= π(12)

^{2 }× 220 cm^{3}= 99565.8 cm

^{3}Now, the height of smaller cylinder (h) = 60 cm

Radius of the base (r) = 8 cm

So, the volume of the smaller cylinder = πr

^{2}h= π(8)2×60 cm

^{3}= 12068.5 cm

^{3}∴ Volume of iron = Volume of the big cylinder+ Volume of the small cylinder

= 99565.8 + 12068.5

=111634.5 cm

^{3}We know,

Mass = Density x volume

So, mass of the pole = 8×111634.5

= 893 Kg (approx.)