Today i am solving the ncert class 10 question of chapter surface areas and volume . Find the easiest and simplest way to solve the exercise 13.2 question number 6 . How i solve the question in a simplest and easiest way.A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass.
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A solid iron pole consists of a cylinder of height 220 cm and base diameter 24 cm, which is surmounted by another cylinder of height 60 cm and radius 8 cm. Find the mass of the pole, given that 1 cm3 of iron has approximately 8 g mass. Q.6
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Given, the height of the big cylinder (H) = 220 cm
Radius of the base (R) = 24/12 = 12 cm
So, the volume of the big cylinder = πR2H
= π(12)2 × 220 cm3
= 99565.8 cm3
Now, the height of smaller cylinder (h) = 60 cm
Radius of the base (r) = 8 cm
So, the volume of the smaller cylinder = πr2h
= π(8)2×60 cm3
= 12068.5 cm3
∴ Volume of iron = Volume of the big cylinder+ Volume of the small cylinder
= 99565.8 + 12068.5
=111634.5 cm3
We know,
Mass = Density x volume
So, mass of the pole = 8×111634.5
= 893 Kg (approx.)