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A right triangle whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed. (Choose value of π as found appropriate) Q.2

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Find the solution of chapter surface areas and volumes of ncert class 10th ,give me the best solution of the exercise 13.5 question number 2 . Also find the easiest and best way to solve this tricky question .A right triangle whose sides are 3 cm and 4 cm (other than hypotenuse) is made to revolve about its hypotenuse. Find the volume and surface area of the double cone so formed. (Choose value of π as found appropriate)

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  1. Draw the diagram as follows:

    Ncert solutions class 10 chapter 13-32

    Let us consider the ABA

    Here,

    AS = 3 cm, AC = 4 cm

    So, Hypotenuse BC = 5 cm

    We have got 2 cones on the same base AA’ where the radius = DA or DA’

    Now, AD/CA = AB/CB

    By putting the value of CA, AB and CB we get,

    AD = 2/5 cm

    We also know,

    DB/AB = AB/CB

    So, DB = 9/5 cm

    As, CD = BC-DB,

    CD = 16/5 cm

    Now, volume of double cone will be

    Ncert solutions class 10 chapter 13-33

    Solving this we get,

    V = 30.14 cm3

    The surface area of the double cone will be

    Ncert solutions class 10 chapter 13-34

    = 52.75 cm2

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