How i solve the chapter areas related to circles of ncert class 10 of exercise 12.2 question number 8(1)(2) . Please find the best and easiest way to solve this tricky question give me the simplest way to solve this question.A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see Fig. 12.11). Find (i) the area of that part of the field in which the horse can graze. (ii) the increase in the grazing area if the rope were 10 m long instead of 5 m. (Use π = 3.14)

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# A horse is tied to a peg at one corner of a square shaped grass field of side 15 m by means of a 5 m long rope (see Fig. 12.11). Find (i) the area of that part of the field in which the horse can graze. (ii) the increase in the grazing area if the rope were 10 m long instead of 5 m. (Use π = 3.14) Q.8(1),(2)

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As the horse is tied at one end of a square field, it will graze only a quarter (i.e. sector with θ = 90°) of the field with radius 5 m.

Here, the length of rope will be the radius of the circle i.e. r = 5 m

It is also known that the side of square field = 15 m

(i)Area of circle = πr^{2 }= 22/7 × 5^{2}= 78.5 m^{2}Now, the area of the part of the field where the horse can graze = ¼ (the area of the circle) = 78.5/4 = 19.625 m

^{2}(ii)If the rope is increased to 10 m,Area of circle will be = πr

^{2}=22/7×10^{2}= 314 m^{2}Now, the area of the part of the field where the horse can graze = ¼ (the area of the circle)

= 314/4 = 78.5 m

^{2}∴ Increase in the grazing area = 78.5 m

^{2}– 19.625 m^{2}= 58.875 m^{2}