Give me the best and simple way for solving the question of class 9^{th} of Surface areas and Volumes chapter of math of question no.6 how i solve this question in easy and simple way because it is very important type of question A hemi spherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7)

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# A hemi spherical tank is made up of an iron sheet 1cm thick. If the inner radius is 1 m, then find the volume of the iron used to make the tank. (Assume π = 22/7) Q.6

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Inner Radius of the tank, (r ) = 1m

Outer Radius (R ) = 1.01m

Volume of the iron used in the tank = (2/3) π(R

^{3}– r^{3})Put values,

Volume of the iron used in the hemispherical tank = (2/3)×(22/7)×(1.01

^{3}– 1^{3}) = 0.06348So, volume of the iron used in the hemispherical tank is 0.06348 m

^{3}.