Newbie

# A bucket is in the form of a frustum of a cone. Its depth is 15 cm and the diameters of the top and the bottom are 56 cm and 42 cm, respectively. Find how many liters of water can the bucket hold.

• 0

To solve this problem use π=22/7

In this problem  a bucket is in the form of a frustum of a cone.

This question was asked in 2005 cbse board exam. Question from RS Aggarwal book chapter volume and surface area of solid, page number 823, exercise 17C, problem number 7

Share

1. solution

given data

Depth of the bucket = height of frustum = h = 15 cm

Diameter of top of bucket = 56 cm

Radius of top = R = 56/2 = 28 cm

Diameter of bottom of bucket = 42 cm

Radius of bottom = r = 42/2 = 21 cm

Volume of frustum of cone = [1/3] π h(R2 + r2 + Rr)

= [1/3] * [22/7] * 15(282 + 212 + 28×21)

= 22 * 5* 259

= 28490

Volume of water bucket can hold = volume of bucket which is in form of frustum

∴volume of water bucket can hold is 28490 cm3

∴ volume of water bucket can hold is 28.49 liter

• 0