To solve this problem use π=22/7
In this problem a bucket is in the form of a frustum of a cone.
This question was asked in 2005 cbse board exam. Question from RS Aggarwal book chapter volume and surface area of solid, page number 823, exercise 17C, problem number 7
solution
given data
Depth of the bucket = height of frustum = h = 15 cm
Diameter of top of bucket = 56 cm
Radius of top = R = 56/2 = 28 cm
Diameter of bottom of bucket = 42 cm
Radius of bottom = r = 42/2 = 21 cm
Volume of frustum of cone = [1/3] π h(R2 + r2 + Rr)
= [1/3] * [22/7] * 15(282 + 212 + 28×21)
= 22 * 5* 259
= 28490
Volume of water bucket can hold = volume of bucket which is in form of frustum
∴volume of water bucket can hold is 28490 cm3
∴ volume of water bucket can hold is 28.49 liter