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AnilSinghBoraGuru

The side AB of a parallelogram ABCD is produced to any point P. A line through A and parallel to CP meets CB produced at Q and then parallelogram PBQR is completed (see Fig. 9.26). Show that ar(ABCD) = ar(PBQR). [Hint : Join AC and PQ. Now compare ar(ACQ) and ar(APQ).] Q.9

what is the tricky way for solving the question of class 9th ncert math of Areas of Parallelograms and Triangles ...Read more

AnilSinghBoraGuru

Hello sir i want to know the best solution of the question from exercise 10.1of math of Circles chapter of ...Read more

AnilSinghBoraGuru

How can i solve this tough question of class 9th ncert of Circles of math of exercise 10.5 of question ...Read more

AnilSinghBoraGuru

Please give me the best way for solving the problem of class 9th ncert math of Heron’s Formula chapter of ...Read more

AnilSinghBoraGuru

How i solve the question of class 9th ncert math of Surface areas and Volumes chapter of exercise 13.3 ...Read more

AnilSinghBoraGuru

sir what is the best way for solving the question of class 9th chapter of Surface areas and Volumes chapter ...Read more

AnilSinghBoraGuru

Asked: March 21, 2022In: CBSE

This is a very important question from NCERT book class 10 chapter 1 Real number. Here in this question, we ...Read more

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