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The radii of two circles are 8 cm and 6 cm, respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles. Q.2

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In ncert class 10 the chapter Areas Related To Circles what is the best solution of exercise 12.1 question number 2 , please help me to solve this question in a easiest and simple way .The radii of two circles are 8 cm and 6 cm, respectively. Find the radius of the circle having area equal to the sum of the areas of the two circles.

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  1. Radius of 1st circle = 8 cm (given)

    ∴ Area of 1st circle = π(8)2 = 64π

    Radius of 2nd circle = 6 cm (given)

    ∴ Area of 2nd circle = π(6)2 = 36π

    So,

    The sum of 1st and 2nd circle will be = 64π+36π = 100π

    Now, assume that the radius of 3rd circle = R

    ∴ Area of the circle 3rd circle = πR2

    It is given that the area of the circle 3rd circle = Area of 1st circle + Area of 2nd circle

    Or, πR2 = 100πcm2

    R2 = 100cm2

    So, R = 10cm

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