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The radii of two circles are 19 cm and 9 cm respectively. Find the radius of the circle which has a circumference equal to the sum of the circumferences of the two circles.Q.1

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Find the best solution of ncert class 10 areas related to circles . How i solve the exercise 12.1 question number 1 please give me the easiest and best solution of this solution.The radii of two circles are 19 cm and 9 cm respectively. Find the radius of the circle which has a circumference equal to the sum of the circumferences of the two circles.

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  1. The radius of the 1st circle = 19 cm (given)

    ∴ Circumference of the 1st circle = 2π×19 = 38π cm

    The radius of the 2nd circle = 9 cm (given)

    ∴ Circumference of the 2nd circle = 2π×9 = 18π cm

    So,

    The sum of the circumference of two circles = 38π+18π = 56π cm

    Now, let the radius of the 3rd circle = R

    ∴ The circumference of the 3rd circle = 2πR

    It is given that sum of the circumference of two circles = circumference of the 3rd circle

    Hence, 56π = 2πR

    Or, R = 28 cm.

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