Find the solution of the ncert class 10 of introduction of trigonometry of exercise 8.2 please help me to solve the question number 2(2) easily and quickly and give me the best solution of the introduction of trigonometry .Show that: (ii) cos 38° cos 52° – sin 38° sin 52° = 0.
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cos 38° cos 52° – sin 38° sin 52°
Simplify the given problem by converting some of the cos functions to the sin functions
We know that,
cos 38° = cos (90° – 52°) = sin 52°
cos 52°= cos (90°-38°) = sin 38°
= cos (90° – 52°) cos (90°-38°) – sin 38° sin 52°
Substitute the values
= sin 52° sin 38° – sin 38° sin 52° = 0