What is the best solution of coordinate geometry . How i solve the question of exercise 7.3 easily and give me best solution with trick of coordinate geometry.Find the area of the triangle whose vertices are: (i) (2, 3), (-1, 0), (2, -4).
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Find the area of the triangle whose vertices are: (i) (2, 3), (-1, 0), (2, -4). Q.1(1)
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Area of a triangle formula = 1/2 × [x1(y2 – y3) + x2(y3 – y1) + x3(y1 – y2)]
(i) Here,
x1 = 2, x2 = -1, x3 = 2, y1 = 3, y2 = 0 and y3 = -4
Substitute all the values in the above formula, we get
Area of triangle = 1/2 [2 {0- (-4)} + (-1) {(-4) – (3)} + 2 (3 – 0)]
= 1/2 {8 + 7 + 6}
= 21/2
So, area of triangle is 21/2 square units.