ICSE & CBSE Board Question Based on Arithmetic Progression of RS Aggarwal
In this Question three consecutive terms of an AP is given you have to find the value of term(x).
This is the Question Number 2 Of Exercise 11D of RS Aggarwal Solution
Deepak BoraNewbie
If (x+2),2x,(2x+3) are three consecutive terms of an AP, find the value of x.
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A.P = x+2 , 2x , 2x+3
d= a2 – a1 = a3 – a2
2x – (x+2) = 2x + 3 – (2x)
2x – x – 2 = 2x + 3 – 2x
x – 2 = 3
x = 3 + 2
x = 5