This question is taken from trigonometry topic trigonometric identities in which we have given that cotθ=1/√3, we have been asked to find the value of (1-cos²θ)/(2-sin²θ) using trigonometric formulas
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 13C, question no 22
cotθ=1/√3
⇒cotθ=cot60°
⇒θ=60°
∴(1-cos²θ)/(2-sin²θ)
Putting the value of θ we get,
=(1-cos²60°)/(2-sin²60°)
=[1-(1/2)²]/[2-(√3/2)²]
=(1-1/4)/(2-3/4)
=(4-1)/4/(8-3)/4
=3/4/5/4
=3/5