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AnilSinghBora
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Find the smallest number which when increased by 20 is exactly divisible by 90 and 144.

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In this question, we have to find the smallest number which when increased by 20 is exactly divisible by 90 and 144. This is an important question from Chapter 1 real number ncert book CBSE board.

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1 Answer

  1. First we will find the LCM of given numbers 

    i.e

    18×5×8=720

    Required smallest number

    720-20=700

    Hence answer is 700

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