This question is from trigonometry
Topic – trigonometric ratios on complementary angles
We have to prove that tan48°tan23°tan42°tan67° = 1
RS Aggarwal, Class 10, chapter 12, question no 3(vi).
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tan 48° tan 23° tan 42° tan 67°
= tan (90° – 42°) tan (90° – 67°) tan 42° tan 67°
= cot 42° cot 67° tan 42° tan 67°
= (cot 42° tan 42°) (cot 67° tan 67°)
= 1×1
= 1