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AnilSinghBora
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Without actually calculating the cubes, find the value of each of the following:(ii) (28)3+(−15)3+(−13)3 Q.14(2)

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Yesterday i was doing the question from class 9th ncert book of math of Polynomials chapter of exercise 2.5. What is the easiest way for solving it because i was not able to do this question please help me for solving this question Without actually calculating the cubes, find the value of each of the following:(ii) (28)3+(−15)3+(−13)3

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  1. (28)3+(−15)3+(−13)3

    Let a = 28

    b = −15

    c = −13

    We know that if x+y+z = 0, then x3+y3+z3 = 3xyz.

    Here, x+y+z = 28–15–13 = 0

    (28)3+(−15)3+(−13)3 = 3xyz

    = 0+3(28)(−15)(−13)

    = 16380

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