An important question from arithmetic progression chapter in which we have been asked to find which term of the AP 5/6, 1, 1 1/6, 1 1/3,….is 3?
Book – RS AGGARWAL, arithmetic progression, chapter 5A, question no 12
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Given,
a=5/6
d=1−5/6=1/6
an=3
an=a+(n−1)d
3=5/6+(n−1)1/6
18=5+n−1
∴n=14