What is the best way for solving the question from class 9^{th} ncert math of Surface areas and Volumes chapter of Ncert of exercise 13.3 of math. What is the best way for solving this question please guide me the best way for solving this question. What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm. [Use π=3.14]

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# What length of tarpaulin 3 m wide will be required to make conical tent of height 8 m and base radius 6m? Assume that the extra length of material that will be required for stitching margins and wastage in cutting is approximately 20 cm. [Use π=3.14] Q.5

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Height of conical tent, h = 8m

Radius of base of tent, r = 6m

Slant height of tent, l

^{2}= (r^{2}+h^{2})l

^{2 }= (6^{2}+8^{2}) = (36+64) = (100)or l = 10

Again, CSA of conical tent = πrl

= (3.14×6×10) m

^{2}= 188.4m

^{2}Let the length of tarpaulin sheet required be L

As 20 cm will be wasted, therefore,

Effective length will be (L-0.2m).

Breadth of tarpaulin = 3m (given)

Area of sheet = CSA of tent

[(L–0.2)×3] = 188.4

L-0.2 = 62.8

L = 63

Therefore, the length of the required tarpaulin sheet will be 63 m.