3 Deepak Bora Asked: July 6, 20202020-07-06T06:13:44+05:30 2020-07-06T06:13:44+05:30In: CBSE What is modulus function in the form of fraction?? 3 please help me with the answer Share Facebook Related Questions Prove that: (secθ+tanθ)/(secθ-tanθ) = (secθ+tanθ)² = 1+2tan²θ+2secθtanθ Prove that: (cosecθ + cotθ)/(cosecθ - cotθ) = (cosecθ + cotθ)² = 1 + 2cot²θ + 2cosecθcotθ Prove that: (1+cosθ-sin²θ)/sinθ(1+cosθ) = cotθ Prove that: (sinθ+cosθ)/(sinθ-cosθ) + (sinθ-cosθ)/(sinθ+cosθ) = 2/(1-2cos²θ) Prove that: (sinθ-cosθ)/(sinθ+cosθ) + (sinθ+cosθ)/(sinθ-cosθ) = 2/(sin²θ-1) 1 Answer Voted Oldest Recent Deepak Bora 2020-07-06T06:45:58+05:30Added an answer on July 6, 2020 at 6:45 am This answer was edited. Hello, It is not a modal function. It is a modulus function. We can have modulus function in fractions like mod(-0.5) will give us answer as 0.5 and so on. We also have modulus in fractional functions as in | (x-1) / (x-2) | which inverts all the negative parts of the function as positive i.e. reflect them about x-axis on the graph. 0 Reply Share Share Share on Facebook Share on Twitter Share on LinkedIn Share on WhatsApp Leave an answerLeave an answerCancel reply Featured image Select file Browse Add a Video to describe the problem better. Video type Youtube Vimeo Dailymotion Facebook Choose from here the video type. Video ID Put Video ID here: https://www.youtube.com/watch?v=sdUUx5FdySs Ex: "sdUUx5FdySs". Click on image to update the captcha. Save my name, email, and website in this browser for the next time I comment.