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Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboid pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 cm?

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ICSE Board Question Based on Mensuration Chapter of M.L Aggarwal for class10
Water is flowing at the rate of 15 km/h through a pipe of diameter 14 cm into a cuboid pond which is 50 m long and 44 m wide. In what time will the level of water in the pond rise by 21 cm?
This is the Question Number 28, Exercise 17.5 of M.L Aggarwal.

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1 Answer

  1. Given speed of water flow = 15 km/h

    Diameter of pipe = 14 cm

    So radius of pipe, r = 14/2 = 7 cm = 0.07 m

    Dimensions of cuboidal pond = 50 m × 44 m

    Height of water in pond = 21 cm = 0.21 m

    So volume of water in pond = 50×44 ×0.21

    = 462 m3

    Volume of water in pipe = r2h

    = ×0.072×h

    = 0.0049h

    Volume of water in pond = Volume of water in pipe

    462 = 0.0049h

    h = 462/0.0049

    = 462×7/0.0049×22

    = 30000 m

    = 30 km [1 km = 1000 m]

    Speed = distance/ time

    Time = Distance/speed = 30/15 = 2 hr

    Hence the time taken is 2 hours.

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