Please give me the best way for solving the problem of class 9th ncert math of Polynomials chapter of math of class 9th of exercise 2.5 of question no 9(2) what is the tricky way for solving this question Verify:(ii) x3–y3 = (x–y)(x2+xy+y2)
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We know that,(x–y)3 = x3–y3–3xy(x–y)
⇒ x3−y3 = (x–y)3+3xy(x–y)
⇒ x3−y3 = (x–y)[(x–y)2+3xy]
Taking (x+y) common ⇒ x3−y3 = (x–y)[(x2+y2–2xy)+3xy]
⇒ x3+y3 = (x–y)(x2+y2+xy)