One of the basic and conceptual question from trigonometric ratios in which we have to show that
sin 60° cos 30° – cos 60° sin 30° = sin 30°
RS Aggarwal, class 10, chapter 11, question no 11(i).
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Consider the L.H.S
sin60∘cos30∘−cos60∘sin30∘
Since,
sin(A−B)=sinAcosB−cosAsinB
Therefore,
=sin(60∘−30∘)
=sin30∘
Hence, proved.