We have been asked to find the HCF and LCM of 21, 28, 36 and 45 by using the method of prime factorization.
This question is taken from real numbers chapter
Kindly give me a detailed solution of this question
RS Aggarwal, Class 10, chapter 1B, question no 2(vi)
prime factors of 21,28,36,45
21=3×7
28=2×2×7=2²×7
36=2×2×3×3=2²×3²
45=5×3×3=5×3²
HCF (21,28,36,45)=1
LCM (21,28,36,45)= 2²×3²×5×7=1260