An Important question based on Linear Equations in two Variables Chapter of R.S Aggarwal book for ICSE &

CBSE Board.

Here Given :

(i) Two years ago, a man was five times as old as his son.

(ii) Two years later, his age will be 8 more than three times the age of his son.

You have to find their present ages.

This is the Question Number 43 Exercise 3E of RS Aggarwal Solution.

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# Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the age of his son. Find their present ages.

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Let the present age of son be x.

According to condition, before 2 years

Age of son = x-2

Age of man = 5(x-2)=5x-10

Present age of man = 5x – 8

After two years,

Man’s age = 5x – 6

Son’s age = x + 2

According to question, after 2 years

Father’s age = 3(son’s age) + 8

5x -6 = 3(x + 2) + 8

5x -6= 3x + 6 + 8

5x -3x = 14 +6

2x = 20

x = 20/2=10

Present age of son = 10 years

Present age of father= 5Ã—10-8 = 42 years