An Important question based on Linear Equations in two Variables Chapter of R.S Aggarwal book for ICSE &
CBSE Board.
Here Given :
(i) Two years ago, a man was five times as old as his son.
(ii) Two years later, his age will be 8 more than three times the age of his son.
You have to find their present ages.
This is the Question Number 43 Exercise 3E of RS Aggarwal Solution.
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Two years ago, a man was five times as old as his son. Two years later, his age will be 8 more than three times the age of his son. Find their present ages.
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Let the present age of son be x.
According to condition, before 2 years
Age of son = x-2
Age of man = 5(x-2)=5x-10
Present age of man = 5x – 8
After two years,
Man’s age = 5x – 6
Son’s age = x + 2
According to question, after 2 years
Father’s age = 3(son’s age) + 8
5x -6 = 3(x + 2) + 8
5x -6= 3x + 6 + 8
5x -3x = 14 +6
2x = 20
x = 20/2=10
Present age of son = 10 years
Present age of father= 5×10-8 = 42 years