This is the basic and exam oriented question from linear equations in two variables in which we have to find the age of father and son if 2 years ago, a father was five times as old as his son. 2 years later, his age will be 8 more than three times the age of the son.
Kindly solve the above problem
RS Aggarwal, Class 10, chapter 3E, question no 43
Let father age be x, his son age be y.
Before 2 years,
⇒(x−2)=5(y−2)−−−−−−−(1)
After 2 years
⇒(x+2)=8+3(y+2)−−−−−−−−(2)
From (1) x−5y+8=0
From (2)
⇒x+2−3y−6−8=0
⇒x−3y−12=0
Solving them
⇒−2y+20=0
⇒y=10
When y=10,x=42
So the present age of the father is 42 and the son age is 10.