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Rajan@2021
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Guru

Two years ago, a father was five times as old as his son. Two years later, his age will be 8 more than three times the age of the son. Find the present ages of father and son.

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This is the basic and exam oriented question from linear equations in two variables in which we have to find the age of father and son if 2 years ago, a father was five times as old as his son. 2 years later, his age will be 8 more than three times the age of the son.

Kindly solve the above problem

RS Aggarwal, Class 10, chapter 3E, question no 43

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1 Answer

  1. Let father age be x, his son age be y.

    Before 2 years,

    (x2)=5(y2)(1)

    After 2 years
    (x+2)=8+3(y+2)(2)

    From (1) x5y+8=0

    From (2)
    x+23y68=0

    x3y12=0

    Solving them
    2y+20=0

    y=10

    When y=10,x=42

    So the present age of the father is 42 and the son age is 10.

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